摘要: flag = 'xxxxxxxxxxxxxxxxxxxxx' s = 'wesyvbniazxchjko1973652048@$+-&*<>' result = '' for i in range(len(flag)): s1 = ord(flag[i])//17 s2 = ord(flag[i]) 阅读全文
posted @ 2022-03-21 20:31 Luccky 阅读(141) 评论(0) 推荐(0) 编辑