摘要: //计算和差积商余数#includeint main(void){ int num1,num2; double y; char op; printf("type in an expression:"); scanf("%d%c%d",&num1,&op,&num2); printf("%d%c%d",num1,op,num2); if(op=='+'){ y=num1+num2; printf("=%.2f\n",y); } else if(op=='-'){ 阅读全文
posted @ 2013-10-20 12:07 刘丽娜123456 阅读(157) 评论(1) 推荐(0) 编辑