poj 1426 Find The Multiple (BFS)
Find The Multiple
Time Limit: 1000MS | Memory Limit: 10000K | |||
Total Submissions: 22121 | Accepted: 9081 | Special Judge |
Description
Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.
Input
The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.
Output
For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.
Sample Input
2 6 19 0
Sample Output
10 100100100100100100 111111111111111111
Source
Dhaka 2002
1404010917 | 1426 | Accepted | 5048K | 407MS | G++ | 475B | 2015-08-20 10:17:35 |
#include<stdio.h> #include<string.h> #include<iostream> #include<algorithm> #include<queue> using namespace std; int n; long long bfs(){ queue<long long >q; q.push(1); while(1){ long long temp=q.front(); q.pop(); if(temp%n==0) return temp; q.push(temp*10); q.push(temp*10+1); } } int main(){ //int t; while(scanf("%d",&n)!=EOF){ if(n==0) break; printf("%lld\n",bfs()); } return 0; }