以守护进程方式启动firefly
原地址:http://www.9miao.com/question-15-53966.html
最近看源码,查了半天,没找到已守护进程方式启动firefly的方法,自己改了改写了一个,废话不多说直接上代码。
startmaster.py 修改后的代码
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#coding:utf8
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import os
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import sys
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from twisted.python import log
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class Launcher:
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def __init__(self):
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self.serverInit()
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self.daemonize()
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self.startServer()
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def daemonize(self):
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try:
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pid = os.fork()
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if pid > 0:
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sys.exit(0)
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except OSError,e:
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log.msg("Fork 1 has failed --> %d--[%s]\n" % (e.errno,e.strerror))
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sys.exit(1)
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os.setsid()
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try:
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pid = os.fork()
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if pid > 0:
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log.msg("Daemon process pid %d" % pid)
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sys.exit(0)
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except OSError, e:
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log.msg("Fork 2 has failed --> %d--[%s]" % (e.errno, e.strerror))
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sys.exit(1)
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def serverInit(self):
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if os.name!='nt' and os.name!='posix':
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from twisted.internet import epollreactor
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epollreactor.install()
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def startServer(self):
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from firefly.master.master import Master
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master = Master()
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master.config('config.json','appmain.py')
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master.start()
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if __name__=="__main__":
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Launcher()
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~