codeforces #519 A A. Multiplication Table (暴力)
Let's consider a table consisting of n rows and n columns. The cell located at the intersection of i-th row and j-th column contains number i × j. The rows and columns are numbered starting from 1.
You are given a positive integer x. Your task is to count the number of cells in a table that contain number x.
The single line contains numbers n and x (1 ≤ n ≤ 105, 1 ≤ x ≤ 109) — the size of the table and the number that we are looking for in the table.
Print a single number: the number of times x occurs in the table.
10 5
2
6 12
4
5 13
0
A table for the second sample test is given below. The occurrences of number 12 are marked bold.
![](http://codeforces.com/predownloaded/73/96/7396f9adf8eaaf460e1588505b9c25ae438f0e8a.png)
我的内心是崩溃的。。。
20天没写代码。。。
然后这道谁题。。。竟然wa了两次。。。
其实思路是没有错的。。。
然后自作聪明得想优化。。。
把优化去掉就A了。。
慢慢恢复感觉==
哦,光扯了。
这道题很显然。。。x出现的话,在每一行只可能出现0次或1次。。
要同时满足 x%i==0 和 x/i<=n
/******************************************************************* Author :111qqz *******************************************************************/ #include <algorithm> #include <cstdio> #include <iostream> #include <cstring> #include <string> #include <cmath> #include <map> #include <stack> #include <queue> #include <set> using namespace std; typedef long long LL; typedef unsigned long long ULL; const int inf = 0x7fffffff; int main() { int n,x; int ans= 0; cin>>n>>x; for ( int i = 1 ; i <= n ; i++) { if (x%i==0 && x/i<=n) { ans++; } } cout<<ans<<endl; return 0; }