nyoj 次方求模

http://acm.nyist.net/JudgeOnline/problem.php?pid=102

View Code 
 1 #include<stdio.h>
 2 int main()
 3 {
 4     long long a,b,n;
 5     int t;
 6     scanf("%d",&t);
 7     while(t--)
 8     {
 9         long long t=1;
10         scanf("%lld%lld%lld",&a,&b,&n);
11         for(;b;b>>=1,a=a*a%n)
12         {
13             if(b%2) t=t*a%n;
14         }
15         printf("%lld\n",t);
16     }
17 }

标程

View Code 
 1  
 2 #include<iostream>
 3 using namespace std;
 4 template<class IntType>
 5 inline IntType ModPow(IntType m,IntType n,IntType p) //m的n次方模p
 6 {
 7     if (n==1) return m%p;
 8         IntType tmp=ModPow(m,n>>1,p);
 9     return (tmp*tmp%p)*((n%2?m:1)%p)%p;
10 }
11 int main()
12 {
13     int n;
14     long long a,b,c;
15     cin>>n;
16     while(n--)
17     {
18         cin>>a>>b>>c;
19         cout<<ModPow(a,b,c)<<endl;
20     }
21 }

 

posted on 2012-08-24 20:03  仁者无敌8勇者无惧  阅读(105)  评论(0)  编辑  收藏  举报

导航