java数组实现红包的方法
1 package Hongbao; 2 3 import java.text.DecimalFormat; 4 import java.util.Scanner; 5 6 public class Hongbao { 7 public static void main(String[] args) { 8 Scanner sc=new Scanner(System.in); 9 10 System.out.println("请输入红包金额:"); 11 double money=sc.nextDouble(); 12 13 System.out.println("请输入红包个数:"); 14 int count=sc.nextInt(); 15 16 //有序数组1到99 17 int[] num=new int[100]; 18 for (int i = 1; i < 100; i++) { 19 num[i-1]=i; 20 } 21 22 //有序数组打乱 23 for (int i = 0; i < num.length; i++) { 24 int ran=(int)(Math.random()*100); 25 int temp=num[i]; 26 num[i]=num[ran]; 27 num[ran]=temp; 28 } 29 30 //将分配的红包个数赋给新数组 31 int[] acount=new int[count]; 32 for (int i = 0; i < count; i++) { 33 acount[i]=num[i]; 34 } 35 //冒泡排序 36 for (int i = 0; i < acount.length; i++) { 37 for (int j = 0; j < acount.length-1-i; j++) { 38 if(acount[j]>acount[j+1]){ 39 int temp=acount[j]; 40 acount[j]=acount[j+1]; 41 acount[j+1]=temp; 42 } 43 } 44 } 45 46 //红包分钱算法 47 int[] mon=new int[count]; 48 for (int i = 0; i < count; i++) { 49 if(i==0){ 50 mon[0]=acount[0]; 51 }else if(i>0&&i<count-1){ 52 mon[i]=acount[i]-acount[i-1]; 53 }else{ 54 mon[i]=100-acount[i-1]; 55 } 56 } 57 58 //带钱 59 DecimalFormat df=new DecimalFormat("####0.00");//保留两位小数 60 for (int i = 0; i < mon.length; i++) { 61 System.out.println("第"+(i+1)+"名,领取"+df.format(mon[i]*0.01*money)+"元红包"); 62 } 63 64 } 65 }