摘要: for i in {1..9};do for j in $( seq 1 $i );do echo -n "$j * $i = $(($j*$i))";echo -n $'\t';done;echo;done 脚本方式: #!/bin/bash for i in {1..9} do for j in 阅读全文
posted @ 2022-02-01 14:19 盗哥泡茶去了 阅读(99) 评论(0) 推荐(0) 编辑