PAT1083:List Grades

1083. List Grades (25)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output "NONE" instead.

Sample Input 1:

4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

Mike CS991301
Mary EE990830
Joe Math990112

Sample Input 2:

2
Jean AA980920 60
Ann CS01 80
90 95

Sample Output 2:

NONE

思路
要求按成绩降序输出给定成绩区间学生的信息。考虑到成绩不超过100而且唯一，可以用桶排序的思想来直接排序输出而不用比较。
1.用两种桶name[101]和ID[101]分别存放姓名和ID。
2.用成绩代表桶的下标，把对应成绩的学生信息放入桶中。如Jack CS00001 60 ---等价于--->  name[60] = "Jack"， ID[60] = "CS00001"。
3.根据区间范围输出不为空的桶里面的信息即可。如果范围内的桶都为空输出"NONE"。
代码

#include<iostream>
#include<vector>
#include<string>
using namespace std;
vector<string> name(101);
vector<string> ID(101);

int main()
{
  int N;
  while(cin >> N)
  {
    string n,id;
    for(int i = 0;i < N;i++)
    {
        int grade;
        cin >> n >> id >> grade;
        name[grade] = n;
        ID[grade] = id;
    }
    int j,k;
    bool isNone = true;
    cin >> j >> k;
    for(;k >= j;k--)
    {
        if(name[k] != "")
        {
          isNone = false;
          cout << name[k] << " " << ID[k] << endl;
        }
    }
    if(isNone)
        cout <<"NONE" << endl;
    ID.clear();
    name.clear();
  }
}