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# 作业要求:下述所有代码画图以及分析代码执行流程
# 1、以定义阶段为准,先画出名称空间的嵌套关系图
# 2、然后找到调用函数的位置,写出函数调用时代码的执行过程,涉及到名字的查找时,参照1中画好
# 的嵌套图,标明查找顺序,一层一层直到找到位置

# ===================题目一===================
input=333
def func():
input=444
func()
print(input)

# ===================题目二===================
def func():
print(x)
x=111

func()

# ===================题目三===================
x=1
def func():
print(x)


def foo():
x=222
func()

foo()

# ===================题目四===================
input=111
def f1():
def f2():
# input=333
print(input)
input=222

f2()

f1()

# ===================题目五===================
x=111
def func():
print(x) #
x=222

func()

# ===================题目六===================
x=111

def foo():
print(x,)

def bar():
print(x)

foo()
bar()

# ===================题目七===================
x=1
def func2():
func1()

x=2
def func1():
print(x)

x=3

func2()

# ===================题目八===================
# 1、如下全局变量记录了当前登录用户,编写登录功能,一旦用户登录成功,则将全局变量赋值为当前登录的用户名
# login_user=None
'''
login_user=None
def users(file,user_input,pas):
with open(file, mode='rt', encoding='utf-8') as f1:
for line in f1:
user, word = line.strip().split(':')
if user_input == user and pas == word:
print('登录成功!')
global login_user
login_user=user_input
else:
print('登录失败')

users('dbs.txt','tank','123')
print(login_user)
'''
# 2、针对之前编写的查询余额的功能,添加额外的逻辑:如果用户没有登录,则先执行登录功能
'''
login_user=None
msg = {'0':'退出','1': '充值','2': '转账','3': '提现','4':'查询余额'}
dic={}
tag = True
while tag:
with open('db.txt', mode='rt', encoding='utf-8') as f2:
for line2 in f2:
user2, money = line2.strip().split(':')
dic[user2] = int(money)
msg = "'0':'退出','1': '充值','2': '转账','3': '提现','4':'查询余额'"
print(msg)
cmd = input('请输入命令编号>>: ').strip()
if not cmd.isdigit():
print('必须输入命令编号的数字')
continue
elif cmd not in msg:
print('输入的命令不存在')
continue
else:
if cmd == '4':
if login_user not in dic:
user_input=input('请输入用户名称:')
pas=input('请输入用户密码:')
with open('dbs.txt', mode='rt', encoding='utf-8') as f1:
for line in f1:
user, word = line.strip().split(':')
if user_input == user and pas == word:
user2 = user_input
money = dic[user2]
print(money)
else:
print('登录失败')
else:
user2 = login_user
money = dic[user2]
print(money)
'''
posted on 2020-03-19 15:58  OBOS  阅读(180)  评论(0编辑  收藏  举报