实验2
任务1
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <time.h> 4 5 #define N 5 6 #define N1 397 7 #define N2 476 8 #define N3 21 9 10 int main() { 11 int cnt; 12 int random_major, random_no; 13 14 srand(time(NULL)); 15 16 cnt = 0; 17 while(cnt < N) { 18 random_major = rand() % 2; 19 20 if(random_major) { 21 random_no = rand() % (N2 - N1 + 1) + N1; 22 printf("20248329%04d\n", random_no); 23 } 24 else { 25 random_no = rand() % N3 + 1; 26 printf("20248395%04d\n", random_no); 27 } 28 29 cnt++; 30 } 31 32 return 0; 33 }
line21代码是为了生成397~476的数字后缀
line25代码是为了生成1~21的数字后缀
这个程序的功能是以当前系统时间作为随机种子生成随机数，若为奇数，则为20248329前缀的学号随机生成397~476的后缀，并补0输出，若为偶数，则为20248395前缀的学号生成1~21的后缀，并补0输出，重复5次，输出五行学号
任务2
1 #include <stdio.h> 2 #include <math.h> 3 4 int main() { 5 double a, b, c; 6 double delta, p1, p2; 7 8 while(scanf("%lf%lf%lf", &a, &b, &c) != EOF) { 9 if(a == 0) { 10 printf("a = 0, invalid input\n"); 11 continue; 12 } 13 14 delta = b*b - 4*a*c; 15 p1 = -b/2/a; 16 p2 = sqrt(fabs(delta))/2/a; 17 18 if(delta == 0) 19 printf("x1 = x2 = %.2g\n", p1); 20 else if(delta > 0) 21 printf("x1 = %.2g, x2 = %.2g\n", p1+p2, p1-p2); 22 else { 23 printf("x1 = %.2g + %.2gi, ", p1, p2); 24 printf("x2 = %.2g - %.2gi\n", p1, p2); 25 } 26 } 27 28 return 0; 29 }
任务3
1 #include<stdio.h> 2 #include<stdlib.h> 3 int main(){ 4 char a; 5 while(scanf("%c",&a)!=EOF){ 6 if(a=='r'){ 7 printf("stop!\n"); 8 getchar(); 9 } 10 else if(a=='g'){ 11 printf("go go go\n"); 12 getchar(); 13 } 14 else if(a=='y'){ 15 printf("wait a minute\n"); 16 getchar(); 17 } 18 else{ 19 printf("something must be wrong...\n"); 20 getchar(); 21 } 22 } 23 return 0; 24 }
任务4
1 #include<stdio.h> 2 #include<stdlib.h> 3 int main(){ 4 double x,max,min,s=0; 5 int k=0; 6 printf("输入今日开销,直到输入-1终止\n"); 7 scanf("%lf",&x); 8 max=x; 9 min=x; 10 while(x!=-1){ 11 s=s+x; 12 k++; 13 if(x>max) 14 max=x; 15 if(x<min) 16 min=x; 17 scanf("%lf",&x); 18 19 } 20 printf("今日累计消费总额:%.1f\n",s); 21 printf("今日最高一笔开销：%.1f\n",max); 22 printf("今日最低一笔开销：%.1f\n",min); 23 return 0; 24 25 26 }
任务5
1 #include<stdio.h> 2 int main(){ 3 int a,b,c; 4 while(scanf("%d%d%d",&a,&b,&c)!=EOF){ 5 if(a+b<=c||a+c<=b||b+c<=a) 6 printf("不能构成三角形\n"); 7 else if(a*a+b*b==c*c||a*a+c*c==b*b||b*b+c*c==a*a) 8 printf("直角三角形\n"); 9 else if(a==b&&b==c) 10 printf("等边三角形\n"); 11 else if(a==b||a==c||b==c) 12 printf("等腰三角形\n"); 13 else 14 printf("普通三角形\n"); 15 } 16 return 0; 17 }
任务6
1 #include<stdio.h> 2 #include<stdlib.h> 3 #include<time.h> 4 int main(){ 5 int lucky_day,guess,chance=3; 6 srand(time(NULL)); 7 lucky_day=rand()%30+1; 8 printf("猜猜2024年11月哪一天会是你的lucky_day\n"); 9 printf("开始喽，你有三次机会，猜吧(1~30):"); 10 while(chance>0){ 11 scanf("%d",&guess); 12 if(guess==lucky_day){ 13 printf("哇,猜中了:)\n"); 14 return 0;} 15 if(guess<lucky_day) 16 printf("你猜的日期早了,你的luckt_day还没到呢\n"); 17 if(guess>lucky_day) 18 printf("你猜的日期晚了,你的lucky_day在前面哦\n");
19 if(chance!=1)
20 printf("再猜(1~30):") ;
21 chance--; 22 } 23 printf("次数用光了,偷偷告诉你,11月你的lucky_day是%d号\n",lucky_day); 24 return 0; 25 }
