task 1-1
#include<stdio.h> #include<stdlib.h> #define N 4 int main() { int a[N]={2,0,2,2}; char b[N]={'2','0','2','2'}; int i; printf("sizeof(int)= %d\n",sizeof(int)); printf("sizeof(char)= %d\n",sizeof(char)); printf("\n"); for(i=0;i<N;i++) printf("%p: %c\n",&b[i],b[i]); printf("\n"); for(i=0;i<N;i++) printf("%p; %c\n",&a[i],a[i]); printf("\n"); printf("a= %p\n",a); printf("b=%p\n",b); system("pause"); }
1.是连续存放的,每个元素占4个内存字节单元
2.是连续存放的,每个元素占1个内存字节单元
3.是一样的,是一样的
task1-2
#include<stdio.h> #include<stdlib.h> #define N 2 #define M 3 int main() { int a[N][M]={{1,2,3},{4,5,6}}; char b[N][M]={{'1','2','3'},{'4','5','6'}}; int i,j; for(i=0;i<N;i++) for(j=0;j<M;j++) printf("%p: %d\n",&a[i][j],a[i][j]); printf("\n"); for(i=0;i<N;i++) for(j=0;j<M;j++) printf("%p: %d\n",&b[i][j],b[i][j]); system("pause"); }
1.是,4个
2,是,1个
task 2
#include <stdio.h> #include<stdlib.h> int days_of_year(int year, int month, int day); int main() { int year, month, day; int days; while(scanf("%d%d%d", &year, &month, &day) != EOF) { days = days_of_year(year, month, day); printf("%4d-%02d-%02d是这一年的第%d天.\n\n", year, month, day, days); } system("pause"); } int days_of_year(int year,int month,int day) { int i,s=0; int days[13]={0,31,28,31,30,31,30,31,31,30,31,30,31}; for(i=1;i<month;i++) s+=days[i]; s+=day; if(year %4==0||year%100==0&&year%400!=0) s+=1; return s; }
task 3
#include <stdio.h> #include <stdlib.h> #define N 5 void input(int x[], int n); void output(int x[], int n); double average(int x[], int n); void sort(int x[], int n); int main() { int scores[N]; double ave; printf("录入%d个分数:\n", N); input(scores, N); printf("\n输出课程分数: \n"); output(scores, N); printf("\n课程分数处理: 计算均分、排序...\n"); ave = average(scores, N); sort(scores, N); printf("\n输出课程均分: %.2f\n", ave); printf("\n输出课程分数(高->低):\n"); output(scores, N); system("pause"); return 0; } void input(int x[], int n) { int i; for(i=0; i<n; ++i) scanf("%d", &x[i]); } void output(int x[],int n) { int i; for(i=0;i<n;i++) printf("%d ",x[i]); printf("\n"); } double average (int x[],int n) { int i; double s=0; for(i=0;i<n;i++) s+=x[i]; return s/n; } void sort (int x[],int n) { int i,j,t; for(i=0;i<n;i++) {for(j=0;j<n-1;j++) {if(x[j]<x[j+1]) {t=x[j]; x[j]=x[j+1]; x[j+1]=t; } } } }
task 4
#include <stdio.h> #include <stdlib.h> void dec2n(int x, int n); int main() { int x; printf("输入一个十进制整数: "); scanf("%d", &x); dec2n(x, 2); printf("\n"); dec2n(x, 8); printf("\n"); dec2n(x, 16); system("pause"); } void dec2n(int x,int n) { int a[80]; int i=1,k, j=0; while(x!=0) {i=x%n; a[j++]=i; x=x/n;} for(k=j-1;k>=0;k--) {if(a[k]>9&&a[k]<16) printf("%c",a[k]-10+'A'); else printf("%d",a[k]); } }
task 5
#include<stdio.h> #include<stdlib.h> void blank(int k,int m); int main() { int i,j,n; while(scanf("%d",&n)!=EOF) {for(i=1;i<=n;i++) {for(j=1;j<=i;j++) {printf("%d ",j);} blank(n-i,i); printf("\n"); } } system("pause"); } void blank(int k,int m) {int i; for(i=1;i<=k;i++) printf("%d ",m); }
task 6
#include <stdio.h> #include <stdlib.h> #define N 80 int main() { char views1[N] = "hey, c, i hate u."; char views2[N] = "hey, c, i love u."; char t[N]; int i; printf("original views:\n"); printf("views1:"); for(i=0;views1[i]!='\0';i++) printf("%c",views1[i]); printf("\n"); printf("views2:"); for(i=0;views1[i]!='\0';i++) printf("%c",views2[i]); printf("\n"); for(i=0;i<N;i++) {t[i]=views1[i]; views1[i]=views2[i]; views2[i]=t[i];} printf("swapping\n"); printf("views1:"); for(i=0;views1[i]!='\0';i++) printf("%c",views1[i]); printf("\n"); printf("views2:"); for(i=0;views1[i]!='\0';i++) printf("%c",views2[i]); printf("\n"); system("pause"); }
task 7
#include <stdio.h> #include <stdlib.h> #include <string.h> #define N 5 #define M 20 void bubble_sort(char str[][M], int n); int main() { char name[][M] = {"Bob", "Bill", "Joseph", "Taylor", "George"}; int i; printf("输出初始名单:\n"); for (i = 0; i < N; i++) printf("%s\n", name[i]); printf("\n排序中...\n"); bubble_sort(name, N); printf("\n按字典序输出名单:\n"); for (i = 0; i < N; i++) printf("%s\n", name[i]); system("pause"); } void bubble_sort(char str[][M],int n) { int i,j; char t[M]; for(i=0;i<N;i++) { for(j=0;j<N-1;j++) { if(strcmp(str[j],str[j+1])>0) {strcpy(t,str[j]); strcpy(str[j],str[j+1]); strcpy(str[j+1],t); } } } }
实验总结
1.整体输入字符数组,scanf("%s",a)不加取地址符,a本身就代表地址
2.用scanf输入不能包含空格,想包含用gets()
3.不能用赋值语句将一个字符串,因为地址常量不能被赋值,想赋值,用strcpy函数
4.二位数组的话a[M][N],a[0],a[1]等代表的是一维数组名
5.数组名实际上代表的是连续存储区域的首地址,而不仅仅是一个普通变量