STL

A Uva10815

#include<set>
#include<string>
#include<sstream>//stringstream 
#include<iostream>
using namespace std;
set<string> se;
int main()
{
    string x,y;
    while(cin>>x){
        for (int i = 0; i < x.length(); ++i) 
            if(isalpha(x[i])) x[i]=tolower(x[i]);//isalpha(x[i]) 判断是否为字母，tolower(x[i) 改编为小写字母
            else x[i]=' ';
            stringstream ss(x);//文件流 
            while(ss>>y) se.insert(y);
 
    }
    for (set<string>::iterator j = se.begin(); j !=se.end() ; ++j) {
        cout<<*j<<'\n';
    }
    return 0;
}

C HDU -1412

 1 #include<iostream>
 2 #include<set>
 3 using namespace std;
 4 set<int >se;
 5 int main()
 6 {
 7 
 8     int n,m;
 9     while(scanf("%d%d",&n,&m)!=EOF)
10     {
11         int x;
12         for(int i=0;i<n;i++){
13             scanf("%d",&x);
14             se.insert(x);
15         }
16         for(int i=0;i<m;i++){
17             scanf("%d",&x);
18             se.insert(x);
19         }
20         set<int>::iterator it;
21         int flag=1;
22         for(it=se.begin();it!=se.end();it++)
23         {
24             if(flag)
25             cout<<*it,flag=0;//注意格式最后一个输出后无空格; 
26             else cout<<' '<<*it;
27         }
28         cout<<endl;
29         se.clear();
30     }
31     return 0;
32 }

 

D:HDU - 1263 

 

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 const int MAXN=1e5+10;
 4 const int INF=0x3f3f3f3f;
 5 map<string,map<string,int> >ma;
 6 int main()
 7 {
 8     int T;
 9     scanf("%d",&T);
10     while(T--)
11     {
12         int n;
13         scanf("%d",&n);
14         string name,place;
15         int num;
16         for(int i=0;i<n;i++){
17             cin>>name>>place>>num;
18             ma[place][name]+=num;
19         }
20         map<string,map<string,int> >::iterator it;
21         for(it = ma.begin();it != ma.end();it++){
22             cout<<it->first<<endl;
23             map<string ,int >::iterator it2;
24             for(it2 = it->second.begin(); it2!=it->second.end(); it2++){
25                 cout<<"   |----"<<it2->first<<'('<<it2->second<<')'<<endl;;
26             }
27             it->second.clear();
28         }
29         ma.clear();
30         if(T!=0) cout<<endl;
31     }
32     return 0;
33 }
34 //guangdong
35  //  |----
View Code

 

E-HDU1004

 1 #include<string>
 2 #include<iostream>
 3 #include<map>
 4 #include<string>
 5 using namespace std;
 6 map<string,int>ma;
 7 string s,ans;
 8 int main()
 9 {
10     int n;
11     while(scanf("%d",&n)!=EOF&&n)
12     {
13         string s;
14         for(int i=0;i<n;i++){
15             cin>>s;
16             ma[s]++;
17         }
18         int num=0;
19         
20         for(map<string,int>::iterator it=ma.begin();it!=ma.end();it++)
21         {
22             s=it->first;
23             if(ma[s]>num) {
24                 ans=s;
25                 num=ma[s];
26             } 
27         }
28         cout<<ans<<endl;
29         ma.clear();
30     }
31     
32     
33     return 0;
34 }
View Code

 F-HDU 1251

 1 #include<stdio.h>
 2 #include<string.h>
 3 #include<map>
 4 #include<string>
 5 using namespace std;
 6 map<string,int>ma;
 7 int main()
 8 {
 9     char s[10];
10     while(gets(s))
11     {
12         int x=strlen(s);
13         if(x==0)
14         break;
15         for(int i=x-1;i>=0;i--)
16         {
17             ma[s]++;s[i]='\0';
18         }
19     }
20         while(scanf("%s",s)!=EOF)
21         {
22             printf("%d\n",ma[s]);
23         }
24     
25     return 0;
26 }
View Code
 

G-不重复数字 HYSBZ - 2761 

 

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 map<int ,int >ma;
 4 vector<int >ve;
 5 int main()
 6 {
 7     int n;
 8     scanf("%d",&n);
 9     while(n--)
10     {
11         ma.clear();
12         int m;
13         scanf("%d",&m);
14         int x;
15         for(int i=0;i<m;i++)
16         {
17             scanf("%d",&x);
18             if(ma[x]==0)
19             {
20                 ma[x]++;
21                 ve.push_back(x);
22             }
23             
24         }
25         for(int i=0;i<ve.size();i++)
26         printf("%d ",ve[i]);
27         printf("\n");
28         ve.clear();
29     }
30     return 0; 
31  }
View Code
 

 I- Three Parts of the Array  CodeForces - 1006C 

 

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 
 4 const int MAXN= 2e5+10;
 5 const int INF=0x3f3f3f3f;
 6 int b[MAXN]; 
 7 set<long long > se;
 8 map<long long ,long long> ma;
 9 int main()
10 {
11     int n;
12     scanf("%d",&n);
13     for(int i=0;i<n;i++)
14     {
15         scanf("%d",&b[i]);
16     }
17     long long  len=0,sum=0;
18     for(int i=0;i<n;i++){
19         sum+=b[i]; 
20         len++;
21         se.insert(sum);
22         ma[sum]=len;
23     }
24     long long ans=0;
25     for(int i=0;i<n;i++){
26         sum-=b[i];
27         len--;
28         if(se.count(sum)==1&&ma[sum]+len<=n)
29         {
30             ans=sum;
31             break;
32         }
33     }
34     printf("%lld\n",ans);
35     return 0;
36  }
View Code

 

posted @ 2018-07-20 21:54  岩扉  阅读(385)  评论(0)  编辑  收藏  举报