LeetCode OJ：Reverse Bits（旋转bit位）

Reverse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000).

注意应该做到平台无关性，需要做到这样的话应该声明一个uint32量然后一直向左移，知道得到 0 就可以得到uint32的位数大小 ：

class Solution {
public:
    uint32_t reverseBits(uint32_t n) {
        uint32_t result = 0;
        for(uint32_t i = 1; i != 0; i <<= 1){
            result <<= 1;
            result |= (n & 1);
            n >>= 1;
        }
        return result;
    }
};