实验1
task1-1.c
#include <stdio.h> int main(){ printf(" o \n"); printf("<H>\n"); printf("I I\n"); printf(" o \n"); printf("<H>\n"); printf("I I\n"); return 0; }
task1-2.c
#include <stdio.h> int main(){ printf(" o o \n"); printf("<H> <H>\n"); printf("I I I I\n"); return 0; }
task2.c
#include <stdio.h> int main() { double a, b, c; scanf("%lf%lf%lf", &a, &b, &c); if(a+b>c && b+c>a && a+c>b) printf("能构成三角形\n"); else printf("不能构成三角形\n"); return 0; }
task3.c
#include <stdio.h> int main() { char ans1, ans2; printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有,输入n或N表示没有) : "); ans1 = getchar(); getchar(); printf("\n动手敲代码实践了没? (输入y或Y表示敲了,输入n或N表示木有敲) : "); ans2 = getchar(); if (ans1 == 'y' || ans1 == 'Y' && ans2 == 'y' || ans2 == 'Y') printf("\n罗马不是一天建成的, 继续保持哦:)\n"); else printf("\n罗马不是一天毁灭的, 我们来建设吧\n"); return 0; }
回答问题:删去line9后无法回答第二个问题,直接给出了“罗马”语句
原因:line9中的getchar用来读取下一个标准字符,而没有了之后,就不能继续读取下一个字符
task4.c
#include<stdio.h> int main() { double x, y; char c1, c2, c3; int a1, a2, a3; scanf(" %d %d %d",&a1,&a2,&a3); printf("a1 = %d, a2 = %d, a3 = %d\n",a1,a2,a3); scanf(" %c %c %c", &c1, &c2, &c3); printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3); scanf("%lf %lf", &x, &y); printf("x = %lf, y = %lf\n",x,y); return 0; }
task5.c
#include <stdio.h> int main() { int year; double a; a = 1000000000/(3600*24*365.0); year = (a+0.5)/1; printf("10亿秒约等于%d年\n", year); return 0; }
task6-2.c
#include <stdio.h> #include <math.h> int main() { double x, ans; while(scanf("%lf", &x) != EOF) { ans = pow(x, 365); printf("%.2f的365次方: %.2f\n", x, ans); printf("\n"); } return 0; }
task7
#include <stdio.h> int main() { double f,c; while(scanf("%lf",&c) !=EOF) { f = 1.8*c+32; printf("摄氏度c=%.2f时,华氏度f=%.2f\n",c,f); printf("\n"); } return 0; }
task8.c
#include <stdio.h> #include <math.h> int main() { double a,b,c,s,area; while(scanf("%lf %lf %lf", &a,&b,&c) != EOF) { s = (a+b+c)/2; area = sqrt(s*(s-a)*(s-b)*(s-c)); printf("a = %.0f,b = %.0f,c = %.0f,area = %.3f\n", a,b,c,area); printf("\n"); } return 0; }