poj 1396 All in All【字符串】

水题一道

#include<stdio.h>
#include<string.h>

char a[100001],b[100001];

int main()
{
    while(scanf("%s %s", a, b) != EOF) {
        char *ta = a;
        char *tb = b;
        while(*tb) {
            if(*ta == *tb) {
                ta++, tb++;
            } else {
                tb++;
            }
        }
        if(ta-a == strlen(a)) printf("Yes\n");
        else printf("No\n");
    }
    return 0;
}