后缀表达式 四则运算
![](https://img2022.cnblogs.com/blog/1468919/202207/1468919-20220706200928116-1075479233.png)
https://leetcode.cn/problems/8Zf90G/
func evalRPN(tokens []string) int { stack := make([]int,0) for _, token := range tokens { val, err := strconv.Atoi(token) if err == nil { stack = append(stack, val) } else { //num2和num1的顺序不能搞反 num2:= stack[len(stack)-1] stack = stack[:len(stack)-1] num1:= stack[len(stack)-1] stack = stack[:len(stack)-1] switch token { case "+": stack = append(stack, num1+num2) case "-": stack = append(stack, num1-num2) case "*": stack = append(stack, num1*num2) default: stack = append(stack, num1/num2) } } } return stack[0] }
等风起的那一天,我已准备好一切