方格取数--状压DP or 网络流

题意:http://acm.hdu.edu.cn/showproblem.php?pid=1565

取不相邻的点是权值最大。

这题可以网络流做,暂时先DP一下,网络流明天学一下~~

  1 #define IOS ios_base::sync_with_stdio(0); cin.tie(0);
  2 #include <cstdio>//sprintf islower isupper
  3 #include <cstdlib>//malloc  exit strcat itoa system("cls")
  4 #include <iostream>//pair
  5 #include <fstream>//freopen("C:\\Users\\13606\\Desktop\\草稿.txt","r",stdin);
  6 #include <bitset>
  7 //#include <map>
  8 //#include<unordered_map>
  9 #include <vector>
 10 #include <stack>
 11 #include <set>
 12 #include <string.h>//strstr substr
 13 #include <string>
 14 #include <time.h>// srand(((unsigned)time(NULL))); Seed n=rand()%10 - 0~9;
 15 #include <cmath>
 16 #include <deque>
 17 #include <queue>//priority_queue<int, vector<int>, greater<int> > q;//less
 18 #include <vector>//emplace_back
 19 //#include <math.h>
 20 //#include <windows.h>//reverse(a,a+len);// ~ ! ~ ! floor
 21 #include <algorithm>//sort + unique : sz=unique(b+1,b+n+1)-(b+1);+nth_element(first, nth, last, compare)
 22 using namespace std;//next_permutation(a+1,a+1+n);//prev_permutation
 23 //******************
 24 int abss(int a);
 25 int lowbit(int n);
 26 int Del_bit_1(int n);
 27 int maxx(int a,int b);
 28 int minn(int a,int b);
 29 double fabss(double a);
 30 void swapp(int &a,int &b);
 31 clock_t __STRAT,__END;
 32 double __TOTALTIME;
 33 void _MS(){__STRAT=clock();}
 34 void _ME(){__END=clock();__TOTALTIME=(double)(__END-__STRAT)/CLOCKS_PER_SEC;cout<<"Time: "<<__TOTALTIME<<" s"<<endl;}
 35 //***********************
 36 #define rint register int
 37 #define fo(a,b,c) for(rint a=b;a<=c;++a)
 38 #define fr(a,b,c) for(rint a=b;a>=c;--a)
 39 #define mem(a,b) memset(a,b,sizeof(a))
 40 #define pr printf
 41 #define sc scanf
 42 #define ls rt<<1
 43 #define rs rt<<1|1
 44 typedef long long ll;
 45 const double E=2.718281828;
 46 const double PI=acos(-1.0);
 47 //const ll INF=(1LL<<60);
 48 const int inf=(1<<30);
 49 const double ESP=1e-9;
 50 const int mod=(int)1e9+7;
 51 const int N=(int)1e6+10;
 52 
 53 int ok_num[N];
 54 int dp[2][20000];
 55 int a[25][25];
 56 
 57 bool OK(int n,int x)
 58 {
 59     int F[22];
 60     F[0]=0;
 61     for(int i=1;i<=n;++i)
 62         F[i]=(x>>(n-i))&1;
 63     for(int i=1;i<n;++i)
 64         if(F[i]&&F[i+1])return 0;
 65     return 1;
 66 }
 67 int get(int now,int state,int n)
 68 {
 69     int F[22];
 70     F[0]=0;
 71     for(int i=1;i<=n;++i)
 72         F[i]=(state>>(n-i))&1;
 73 
 74     int temp=0;
 75     for(int i=1;i<=n;++i)
 76         if(F[i])temp+=a[now][i];
 77     return temp;
 78 }
 79 
 80 void solve(int n)
 81 {
 82     int cnt=0;
 83     int tot=(1<<n)-1;
 84     for(int i=0;i<=tot;++i)
 85     {
 86         if(OK(n,i))
 87             ok_num[++cnt]=i;
 88     }
 89 //    cout<<cnt<<endl;
 90     for(int i=1;i<=n;++i)
 91         for(int j=1;j<=n;++j)
 92             sc("%d",&a[i][j]);
 93     for(int i=0;i<=cnt;++i)
 94         dp[0][i]=dp[1][i]=0;
 95     for(int i=1;i<=n;++i)
 96     {
 97         for(int j=1;j<=cnt;++j)
 98         {
 99             int temp=get(i,ok_num[j],n);
100         //    dp[1][j]=temp;
101             for(int k=1;k<=cnt;++k)
102             {
103                 if((ok_num[j]&ok_num[k])==0)
104                     dp[1][j]=maxx(dp[1][j],temp+dp[0][k]);
105             }
106         }
107         for(int j=1;j<=cnt;++j)
108             dp[0][j]=dp[1][j],dp[1][j]=0;
109     }
110     int ans=0;
111     for(int i=1;i<=cnt;++i)
112         ans=maxx(ans,dp[0][i]);
113     pr("%d\n",ans);
114 }
115 
116 int main()
117 {
118     int n;
119     while(~sc("%d",&n))solve(n);
120     return 0;
121 }
122 
123 /**************************************************************************************/
124 
125 int maxx(int a,int b)
126 {
127     return a>b?a:b;
128 }
129 
130 void swapp(int &a,int &b)
131 {
132     a^=b^=a^=b;
133 }
134 
135 int lowbit(int n)
136 {
137     return n&(-n);
138 }
139 
140 int Del_bit_1(int n)
141 {
142     return n&(n-1);
143 }
144 
145 int abss(int a)
146 {
147     return a>0?a:-a;
148 }
149 
150 double fabss(double a)
151 {
152     return a>0?a:-a;
153 }
154 
155 int minn(int a,int b)
156 {
157     return a<b?a:b;
158 }

 

posted @ 2019-10-22 22:21  ZMWLxh  阅读(222)  评论(0编辑  收藏  举报