摘要: 网上找的模版实在是用不惯。。无奈自己写了一个。。。 下面是系数矩阵n*n,增广矩阵n*(n+1)。 最后结果为 z[i]= y[i]/x[i] ,即 x[i] * z[i] =y[i] .矩阵如下 x1 z1 y1 x1 z1 y1 x2 * z2 = y2 或 0 * z2 = 0 x3 z3 = 阅读全文
posted @ 2016-02-12 19:48 __560 阅读(204) 评论(0) 推荐(0) 编辑
摘要: StringsobitsKim Schrijvers Consider an ordered set S of strings of N (1 <= N <= 31) bits. Bits, of course, are either 0 or 1. This set of strings is i 阅读全文
posted @ 2016-02-12 08:20 __560 阅读(255) 评论(0) 推荐(0) 编辑