最大流dinic 模版 (训练指南)
struct Edge { int from,to,cap,flow; }; struct Dinic { int n,m,s,t; vector<Edge> edges; vector<int> G[maxn]; bool vis[maxn]; int d[maxn]; int cur[maxn]; void init(int n) { REP(i,1,n) G[i].clear(); edges.clear(); } void addedge(int from,int to,int cap) { edges.push_back((Edge){from,to,cap,0}); edges.push_back((Edge){to,from,0,0}); m=edges.size(); G[from].push_back(m-2); G[to].push_back(m-1); } bool bfs() { MS0(vis); queue<int> q; q.push(s); d[s]=0; vis[s]=1; while(!q.empty()){ int u=q.front();q.pop(); for(int i=0;i<G[u].size();i++){ Edge& e=edges[G[u][i]]; if(!vis[e.to]&&e.cap>e.flow){ vis[e.to]=1; d[e.to]=d[u]+1; q.push(e.to); } } } return vis[t]; } int dfs(int u,int a) { if(u==t||a==0) return a; int flow=0,f; for(int& i=cur[u];i<G[u].size();i++){ Edge& e=edges[G[u][i]]; if(d[u]+1==d[e.to]&&(f=dfs(e.to,min(a,e.cap-e.flow)))>0){ e.flow+=f; edges[G[u][i]^1].flow-=f; flow+=f; a-=f; if(a==0) break; } } return flow; } int Maxflow(int s,int t) { this->s=s;this->t=t; int flow=0; while(bfs()){ MS0(cur); flow+=dfs(s,INF); } return flow; } };Dinic F;
没有AC不了的题,只有不努力的ACMER!