codeforces#296div2_a 模拟
codeforces#296div2_a 模拟
One day Vasya was sitting on a not so interesting Maths lesson and making an origami from a rectangular a mm × b mm sheet of paper (a > b). Usually the first step in making an origami is making a square piece of paper from the rectangular sheet by folding the sheet along the bisector of the right angle, and cutting the excess part.
After making a paper ship from the square piece, Vasya looked on the remaining (a - b) mm × b mm strip of paper. He got the idea to use this strip of paper in the same way to make an origami, and then use the remainder (if it exists) and so on. At the moment when he is left with a square piece of paper, he will make the last ship from it and stop.
Can you determine how many ships Vasya will make during the lesson?
The first line of the input contains two integers a, b (1 ≤ b < a ≤ 1012) — the sizes of the original sheet of paper.
Print a single integer — the number of ships that Vasya will make.
2 1
2
10 7
6
1000000000000 1
1000000000000
题意:问一张长方形纸能剪成多少个正方形
思路:按题意模拟,竟然是gcd。。。10分钟1A!
#include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #include<algorithm> using namespace std; const int maxn=1000100; const int INF=(1<<28); unsigned long long a,b; unsigned long long s; void solve(unsigned long long a,unsigned long long b) { if(b==0) return; s+=a/b; solve(b,a%b); } int main() { cin>>a>>b; s=0; solve(a,b); cout<<s<<endl; return 0; }