day03 解析库之遍历文档树

html_doc = """
<html><head><title>The Dormouse's story</title></head>
<body>
<p class="sister"><b>$37</b></p>
<p class="story" id="p">Once upon a time there were three little sisters; and their names were
<a href="http://example.com/elsie" class="sister" >Elsie</a>,
<a href="http://example.com/lacie" class="sister" id="link2">Lacie</a> and
<a href="http://example.com/tillie" class="sister" id="link3">Tillie</a>;
and they lived at the bottom of a well.</p>

<p class="story">...</p>
"""
from bs4 import BeautifulSoup

soup = BeautifulSoup(html_doc, 'lxml')
# print(soup)
# print(type(soup))
# 遍历文档树
# 1、直接使用  *****
print(soup.html)
print(type(soup.html))
print(soup.a)
print(soup.p)

# 2、获取标签的名称
print(soup.a.name)

# 3、获取标签的属性   *****
print(soup.a.attrs)  # 获取a标签中所有的属性
print(soup.a.attrs['href'])

# 4、获取标签的文本内容  *****
print(soup.p.text)  # $37

# 5、嵌套选择
print(soup.html.body.p)

# 6、子节点、子孙节点
print(soup.p.children)  # 返回迭代器对象
print(list(soup.p.children))  # [<b>$37</b>]

# 7、父节点、祖先节点
print(soup.b.parent)
print(soup.b.parents)
print(list(soup.b.parents))

# 8、兄弟节点  (sibling: 兄弟姐妹)
print(soup.a)
# 获取下一个兄弟节点
print(soup.a.next_sibling)

# 获取下一个的所有兄弟节点,返回的是一个生成器
print(soup.a.next_siblings)
print(list(soup.a.next_siblings))

# 获取上一个兄弟节点
print(soup.a.previous_sibling)
# 获取上一个的所有兄弟节点,返回的是一个生成器
print(list(soup.a.previous_siblings))

 

posted @ 2019-07-03 17:39  阿泽zzz  阅读(154)  评论(0编辑  收藏  举报