374. Guess Number Higher or Lower

不定期更新leetcode解题java答案。

采用pick one的方式选择题目。

题意为给定一个范围,1~N,给定一个固定数,随机进行猜数,尽快用程序获取猜得结果。每次猜错会给出猜想大了(返回-1)或小了(返回1)的提示。

很容易想到用二分进行猜数(需要注意的是为了防止两数相加和超出int的上限,分开进行处理),代码如下:

 1 /* The guess API is defined in the parent class GuessGame.
 2    @param num, your guess
 3    @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
 4       int guess(int num); */
 5 
 6 public class Solution extends GuessGame {
 7     public int guessNumber(int n) {
 8         int start = 0, end = n, guessNum = 0;
 9         int result = 1;
10         while(result != 0){
11             if(result == 1)
12                 start = guessNum;
13             else
14                 end = guessNum;
15             guessNum = start / 2 + end / 2 + (start % 2 + end % 2 == 0 ? 0 : 1);
16                 
17             result = guess(guessNum);
18         }
19         return guessNum;
20     }
21 }

 

posted @ 2016-10-14 19:53  zslhq~  阅读(152)  评论(0编辑  收藏  举报