#LeetCode# 35. Search Insert Position

https://leetcode.com/problems/search-insert-position/description/

 

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Example 1:

Input: [1,3,5,6], 5
Output: 2

Example 2:

Input: [1,3,5,6], 2
Output: 1

Example 3:

Input: [1,3,5,6], 7
Output: 4

Example 4:

Input: [1,3,5,6], 0
Output: 0

代码:

class Solution {
public:
    int searchInsert(vector<int>& nums, int target) {
        int temp;
        for(int i = 0; i < nums.size(); i ++) {
            if(nums[i] >= target) {
                temp = i;
                break;
            }
            if(nums[nums.size() - 1] < target) 
                return nums.size();
        }
        return temp;
    }
};

  

posted @ 2018-11-05 12:50  丧心病狂工科女  阅读(107)  评论(0编辑  收藏  举报