Java [Leetcode 383]Ransom Note

题目描述：

Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 all 
the 
magazines,
 write 
a 
function 
that 
will 
return 
true 
if 
the 
ransom 
 note 
can 
be 
constructed 
from 
the 
magazines ; 
otherwise, 
it 
will 
return 
false. 



Each 
letter
 in
 the
 magazine 
string 
can
 only 
be
 used 
once
 in
 your 
ransom
 note.

Note:
You may assume that both strings contain only lowercase letters.

canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true

解题思路：

开26个数组存入magzine字母的数目，每个位置存对应字母的数目；

对ransom字符串来说，每读一个字母，则将对应位置的字母数目减一，如果某个字母数目小于0了，则表明字母不够用，从而返回false；否则返回true。

代码如下：

public class Solution {
    public boolean canConstruct(String ransomNote, String magazine) {
    	int[] ran_array = new int[26];
    	for(int i = 0; i < magazine.length(); i++){
    		ran_array[magazine.charAt(i) - 'a']++;
    	}

    	for(int i = 0; i < ransomNote.length(); i++){
    		if(--ran_array[ransomNote.charAt(i) - 'a'] < 0)
    			return false;
    	}

    	return true;
        
    }
}