用数组快速判断n个值是否相等

#include <stdio.h>
#include <stdlib.h>
int judge(int a[]);

int main()
{   int a[10] = {0};
  if(judge(a)==1)
  {
      printf("相等\n");
  }
  else
  {
      printf("不相等\n");
  }

    return 0;
}
int judge(int a[])
{
    int i = 0;
    int resul = 0;
    for(i=0;i<10;i++)

        if(a[0]!=a[i])
        {
            resul = -1;
            break;
        }
        else
        {
           resul = 1;
        }

return resul;

}