0928多线程运行——作业

实验六  多线程编程

1.随便选择两个城市作为预选旅游目标。实现两个独立的线程分别显示10次城市名，每次显示后休眠一段随机时间(1000ms以内)，哪个先显示完毕，就决定去哪个城市。分别用Runnable接口和Thread类实现

package homework;

public  class sj implements Runnable {

	//属性：两个城市
	private int a=10;
	
	//方法
	private synchronized void getCity()
	{
		if(a>10)
		{
			System.out.println("只运行10次");
			return;
		}
		
		a--;
		System.out.println(Thread.currentThread().getName());
	}
	
	@Override
	public void run() {

		while(a>0)
		{
			getCity();
			
			try {
				Thread.sleep(1000);
			} catch (InterruptedException e) {
				// TODO Auto-generated catch block
				e.printStackTrace();
			}
		}
		
	}

}




package homework;

public class test {

	public static void main(String[] args) {
		// TODO Auto-generated method stub

		sj s=new sj();
		
		Thread t1=new Thread(s,"武汉");
		
		t1.start();
			
		Thread t2=new Thread(s,"成都");
		
		t2.start();
		
	}

}