FZU2141——贪心——Sub-Bipartite Graph

http://acm.fzu.edu.cn/problem.php?pid=2141

/*
大意：把一张图分成一个二分图，使得任意相邻的顶点不在同一个集合里面，
*/
/************************************************
* Author        :Powatr
* Created Time  :2015-8-24 14:56:55
* File Name     :FZU2141.cpp
 ************************************************/

#include <cstdio>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <cstring>
#include <cmath>
#include <string>
#include <vector>
#include <queue>
#include <deque>
#include <stack>
#include <list>
#include <map>
#include <set>
#include <bitset>
#include <cstdlib>
#include <ctime>
using namespace std;

#define lson l, mid, rt << 1
#define rson mid + 1, r, rt << 1 | 1
typedef long long ll;
const int MAXN = 1e2 + 10;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9 + 7;

int p1, p2;
int mp[MAXN][MAXN];
int pp[MAXN];
int sum1, sum2;
void check(int x)
{
    int cout1 = 0, cout2 = 0;
    pp[x] = 1;
    for(int i = 1; i < x; i++){
        if(mp[i][x] && pp[x] != pp[i])
            cout1++;
    }
    pp[x] = 2;
    for(int i = 1; i < x; i++){
        if(mp[i][x] && pp[x] != pp[i])
            cout2++;
    }
    if(cout1 > cout2){
        pp[x] = 1;
        sum1++;
    }
    else {
        pp[x] = 2;
        sum2++;
    }
}
int main(){
    int T;
    int n, m, x, y;
    for(scanf("%d", &T); T--; ){
        scanf("%d%d", &n, &m);
        sum1 = sum2 = 0;
        memset(pp, 0, sizeof(pp));
        memset(mp, 0, sizeof(mp));
        for(int i = 1; i <= m; i++){
            scanf("%d%d", &x, &y);
            mp[x][y] = mp[y][x] = 1;
        }
        for(int i = 1; i <= n; i++){
            check(i);
        }
        int c1 = 0, c2 = 0;
        printf("%d%c", sum1, sum1 == 0 ? '\n' : ' ');
        for(int i = 1; i <= n; i++){
            if(pp[i] == 1){
                c1++;
                printf("%d%c", i, c1 == sum1 ? '\n' : ' ');
            }
        }
        printf("%d%c", sum2, sum2 == 0 ? '\n' : ' ');
        for(int i = 1; i <= n; i++){
            if(pp[i] == 2){
                c2++;
                printf("%d%c", i, c2 == sum2 ? '\n' : ' ');
            }
        }
    }
    return 0;
}