Subsets,Subsets II
一.Subsets
Given a set of distinct integers, nums, return all possible subsets.
Note:
- Elements in a subset must be in non-descending order.
- The solution set must not contain duplicate subsets.
For example,
If nums = [1,2,3]
, a solution is:
[ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ]
class Solution { public: void dfs(vector<int>& nums ,int numsSize,int startPos,vector<vector<int>>& res,vector<int>& oneOfRes) { for(int i=startPos;i<numsSize;i++){ oneOfRes.push_back(nums[i]); res.push_back(oneOfRes); dfs(nums,numsSize,i+1,res,oneOfRes); oneOfRes.pop_back(); } } vector<vector<int>> subsets(vector<int>& nums) { sort(nums.begin(),nums.end()); vector<vector<int>> res; vector<int> oneOfRes; res.push_back(vector<int>()); int numsSize = nums.size(); dfs(nums,numsSize,0,res,oneOfRes); return res; } };
二.SubsetsII
Given a collection of integers that might contain duplicates, nums, return all possible subsets.
Note:
- Elements in a subset must be in non-descending order.
- The solution set must not contain duplicate subsets.
For example,
If nums = [1,2,2]
, a solution is:
[ [2], [1], [1,2,2], [2,2], [1,2], [] ]
class Solution { public: void dfs(vector<int>& nums,int numsSize,int startPos,vector<vector<int>>& res,vector<int>& oneOfRes) { for(int i=startPos;i<numsSize;i++){ if(i>startPos && nums[i]==nums[i-1]){ continue; } oneOfRes.push_back(nums[i]); res.push_back(oneOfRes); dfs(nums,numsSize,i+1,res,oneOfRes); oneOfRes.pop_back(); } } vector<vector<int>> subsetsWithDup(vector<int>& nums) { sort(nums.begin(),nums.end()); vector<vector<int>> res; vector<int> oneOfRes; int numsSize = nums.size(); res.push_back(oneOfRes); dfs(nums,numsSize,0,res,oneOfRes); return res; } };
写者:zengzy
出处: http://www.cnblogs.com/zengzy
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