LeetCode 007 Reverse Integer - Java

Reverse digits of an integer.

Example1: x = 123, return 321
Example2: x = -123, return -321

Note:
The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.

 

定位：简单题

将输入的数反转输出，注意的是负数符号保持在最前，反转后的值超出int_32bit范围输出0。

简单的将传如的数分离符号后用StringBuffer进行反转，然后转化为int，此时尝试抓取NumberFormatException的错误，如有直接为0。

 

Java实现：

public class Solution {
    public int reverse(int x) {
        boolean isNev=false;
        if(x<0){
            x=-x;
            isNev=true;
        }
        StringBuffer stringBuffer=new StringBuffer(String.valueOf(x));
        stringBuffer=stringBuffer.reverse();
        int y;
        try{
            y=Integer.parseInt(stringBuffer.toString());
        }catch (NumberFormatException e){
            y=0;
        }
        if(isNev){
            y=-y;
        }
        return y;
    }
}