mysql取差集、交集、并集

mysql取差集、交集、并集

博客分类: Mysql数据库
 
需求:从两个不同的结果集(一个是子集,一个是父集),字段为电话号码phone_number,找出父集中缺少的电话号码,以明确用户身份。 
结合网上资料,整理sql如下: 

//mysql取差集 

Java代码  收藏代码
select num FROM  
(  
  
select u.code_sn as id,u.phone_number as num from t1 b  
left join t2 u  
on b.from_user=u.code_sn  
where b.to_account='1000' and b.json_info like '%09月份%'  
  
union all  
  
select u.code_sn as id,u.phone_number as num from t3 o  
left join t2 u  
on o.buyer_code_sn=u.code_sn  
where o.seller_account_code_sn='1000' and o.json_info like '%09月份%'   
  
)t3  
group by num having count(num)=1  


//mysql取交集 

Java代码  收藏代码
select num FROM  
(  
  
select u.code_sn as id,u.phone_number as num from t1 b  
left join t2 u  
on b.from_user=u.code_sn  
where b.to_account='1000' and b.json_info like '%09月份%'  
  
union all  
  
select u.code_sn as id,u.phone_number as num from t1 o  
left join t2 u  
on o.buyer_code_sn=u.code_sn  
where o.seller_account_code_sn='1000' and o.json_info like '%09月份%'   
  
)t3  
group by num having count(num)=2  


//mysql取并集 

Java代码  收藏代码
select num FROM  
(  
  
select u.code_sn as id,u.phone_number as num from t1 b  
left join t2 u  
on b.from_user=u.code_sn  
where b.to_account='1000' and b.json_info like '%09月份%'  
  
union all  
  
select u.code_sn as id,u.phone_number as num from t1 o  
left join t2 u  
on o.buyer_code_sn=u.code_sn  
where o.seller_account_code_sn='1000' and o.json_info like '%09月份%'   
  
)t3  

 

posted @ 2017-07-17 16:52  雨花梦  阅读(2937)  评论(0编辑  收藏  举报