UVA 12647 Balloon

这是一个线段树的题目;

我记得一个月前在cf上也做过一个类似的题目;

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<algorithm>
 4 #define maxn 100010
 5 #define bon 1000010
 6 using namespace std;
 7 int cover[bon<<2];
 8 int f[maxn<<2],ans[maxn<<2];
 9 struct line
10 {
11     int x1,y1,x2,y2;
12     bool operator<(const line &t)const
13     {
14         return y1<t.y1;
15     }
16 } li[maxn<<2];
17 
18 void pushdown(int rt)
19 {
20     if(cover[rt]>=0)
21     {
22         cover[rt<<1]=cover[rt<<1|1]=cover[rt];
23         cover[rt]=-1;
24     }
25 }
26 
27 int query(int x,int l,int r,int rt)
28 {
29     if(cover[rt]>=0) return cover[rt];
30     int mid=(l+r)>>1;
31     pushdown(rt);
32     if(x<=mid)return query(x,l,mid,rt<<1);
33     else return query(x,mid+1,r,rt<<1|1);
34 }
35 
36 void update(int L,int R,int i,int l,int r,int rt)
37 {
38     if(L<=l&&R>=r)
39     {
40         cover[rt]=i;
41         return;
42     }
43     int mid=(l+r)>>1;
44     pushdown(rt);
45     if(L<=mid)update(L,R,i,l,mid,rt<<1);
46     if(R>mid)update(L,R,i,mid+1,r,rt<<1|1);
47 }
48 int n,q,xx;
49 void solve(int x)
50 {
51     int k=query(x,0,bon,1);
52     if(li[k].y1!=li[k].y2)x=ans[k];
53     if(f[k]==n)printf("%d\n",x);
54     else printf("%d %d\n",x,li[f[k]].y1);
55 }
56 
57 int main()
58 {
59     while(scanf("%d%d",&n,&q)!=EOF)
60     {
61         memset(cover,-1,sizeof cover);
62         for(int i=0; i<n; i++)
63         {
64             scanf("%d%d%d%d",&li[i].x1,&li[i].y1,&li[i].x2,&li[i].y2);
65             if(li[i].y1<li[i].y2)
66             {
67                 swap(li[i].x1,li[i].x2);
68                 swap(li[i].y1,li[i].y2);
69             }
70         }
71         li[n].x1=0,li[n].x2=bon,li[n].y1=bon+1,li[n].y2=bon+1;
72         sort(li,li+n+1);
73         for(int i=n; i>=0; i--)
74         {
75             if(li[i].y1==li[i].y2) f[i]=i;
76             else
77             {
78                 int k=query(li[i].x1,0,bon,1);
79                 f[i]=f[k];
80                 if(li[k].y1==li[k].y2) ans[i]=li[i].x1;
81                 else ans[i]=ans[k];
82             }
83             int l=li[i].x1,r=li[i].x2;
84             if(l>r)swap(l,r);
85             update(l,r,i,0,bon,1);
86         }
87         while(q--)
88         {
89             scanf("%d",&xx);
90             solve(xx);
91         }
92     }
93     return 0;
94 }
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posted @ 2013-11-15 23:02  Yours1103  阅读(619)  评论(0编辑  收藏  举报