day 11字符串 19:11_ 20:13

test="df3\tdfdsfd"
v=test.expandtabs(6)
print(v)//df3 dfdsfd 6个断,遇到\t补齐

test1="df3"
test2="fsd"
v1=test1.isalpha()//是否字母汉字
v2=test2.isalpha()
print(v1)
print(v2)//false true

test1="df3"
test2="fsd"
v1=test1.isalpha()//是否字母汉字
v2=test2.isalpha()
print(v1)
print(v2)//false true

v1=test1.isidentifier()//标识符,关键字也能

13 当前输入是否是数字
# test = "二" # 1,②
# v1 = test.isdecimal()//@里面数字
# v2 = test.isdigit()//十进制。用的更多
# v3 = test.isnumeric()//中文数字也支持
# print(v1,v2,v3)


# 15 判断是否全部是空格
# test = ""
# v = test.isspace()
# print(v)

 

是否能全部显示出来

test1="3eertr"

test2="fsdfA\t"

v1=test1.isprintable()
v2=test2.isspace()
print(v1)
print(v2) //true false

//是否标题首字母大写
test = "oiuas dfkj"
v = test.title()
print(v)
v1=v.istitle()
print(v1)//Oiuas Dfkj True


将字符串中的每一个元素按照指定分隔符进行拼接
test = "oiuas分dfkj"
v = "@#@".join(test)
print(v)//o@#@i@#@u@#@a@#@s@#@分@#@d@#@f@#@k@#@j

# 以什么对齐填充
test = "oiu"
v = test.ljust(10,"@")
ac="qw"
v1=ac.rjust(10,"@")

v2=ac.center(10,"@")
print(v)
print(v1)
print(v)
//oiu@@@@@@@  @@@@@@@@qw   @@@@qw@@@@

# 去掉空格,\t  \r
test = " oiu "
v = test.lstrip()
v1=test.rstrip()
v2=test.strip()
print(test)
print(v)
print(v1)
print(v2)//不写
test = "axoiubx"
v = test.lstrip("ax")
v1=test.rstrip("bx")
print(test)
print(v)
print(v1)//axoiubx oiubx axoiu





 


 

posted @ 2018-06-17 20:12  一棵大树一棵小树一棵草  阅读(120)  评论(0编辑  收藏  举报