ABAP算法题:海盗报数问题。
题目:有一艘海盗船上面有30个海盗,分别为海盗1-30号忽然海盗船撞上了冰山,船上只能留下一个人,船长命令大家循环数数,数到7和7的倍数的人,跳到海里去。
分析: 没什么好分析的。
输入海盗人数,输入死亡数字,输出海盗死亡顺序。
SELECTION-SCREEN BEGIN OF BLOCK b0.
PARAMETERS: p_number TYPE i OBLIGATORY DEFAULT 30.
PARAMETERS: p_keyval TYPE n OBLIGATORY DEFAULT 7.
SELECTION-SCREEN END OF BLOCK b0.
*
**
TYPES: BEGIN OF person,
index(2) TYPE n,
numbr(2) TYPE n,
END OF person.
DATA :t_person TYPE TABLE OF person.
DATA last_number TYPE i.
t_person = VALUE #( FOR i = 1 UNTIL i > p_number ( index = i ) ).
DO.
IF lines( t_person ) < 2.EXIT.ENDIF.
LOOP AT t_person ASSIGNING FIELD-SYMBOL(<s_person>).
<s_person>-numbr = last_number + 1 .
last_number = <s_person>-numbr.
IF <s_person>-numbr MOD p_keyval = 0 .
WRITE: / 'index' ,<s_person>-index,'dead! Number is ', <s_person>-numbr .
DELETE t_person.
CONTINUE.
ENDIF.
SEARCH <s_person>-numbr FOR p_keyval.
IF sy-subrc EQ 0.
WRITE: / 'index' ,<s_person>-index,'dead! Number is ', <s_person>-numbr .
DELETE t_person.
ENDIF.
ENDLOOP.
ENDDO.
READ TABLE t_person ASSIGNING <s_person> INDEX 1.
WRITE :/ 'index', <s_person>-index,'alive '.