ios--django 数据库的链接数据的返回(简单处理)

def testdb(request):
b = models.Book.objects.all()
message = []
for dic in b:
if dic.__dict__['_state']:
dic.__dict__['_state'] = 1
if dic.__dict__['publisher_date']:
a = dic.__dict__['publisher_date']
timeStr = a.strftime('%y-%m-%d')
dic.__dict__['publisher_date'] = timeStr
message.append(dic.__dict__)
return HttpResponse(json.dumps(message))

posted @ 2014-04-04 15:21  功夫杨  阅读(214)  评论(0编辑  收藏  举报