hdu 1020 Encoding
Encoding
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 43496 Accepted Submission(s): 19218
Problem Description
Given a string containing only 'A' - 'Z', we could encode it using the following method:
1. Each sub-string containing k same characters should be encoded to "kX" where "X" is the only character in this sub-string.
2. If the length of the sub-string is 1, '1' should be ignored.
1. Each sub-string containing k same characters should be encoded to "kX" where "X" is the only character in this sub-string.
2. If the length of the sub-string is 1, '1' should be ignored.
Input
The first line contains an integer N (1 <= N <= 100) which indicates the number of test cases. The next N lines contain N strings. Each string consists of only 'A' - 'Z' and the length is less than 10000.
Output
For each test case, output the encoded string in a line.
Sample Input
2 ABC ABBCCC
Sample Output
ABC A2B3C题意是说假如输入“AABBAA” 应输入2A2B2A(坑在这)#include<iostream> #include<string> #include<math.h> #include<string.h> #include<stdio.h> #include<algorithm> #include<map> using namespace std; int main() { int num,j,k,i; cin>>num; while(num--) { string s1; int sum=0,k=0; cin>>s1; sum=0; for(i=1;i<=s1.size();i++) { if(s1[i]!=s1[i-1]) { sum=i-k+1-1; if(sum==1) cout<<s1[i-1]; else cout<<sum<<s1[i-1]; k=i; } } cout<<endl; } return 0; }