判断json 对象是否相同的方法

    var arr = [1, 2, 3, { a: 1, b: 4},[2,8]]
    var arr2 = [1, 2, 3, { b: 4, a: 1 }, [2, 8]]
    Array.prototype.equals = function (array) {
      if (!array)
        return false;
      if (this.length != array.length)
        return false;
      for (var i = 0, l = this.length; i < l; i++) {
        // Check if we have nested arrays
        if ((this[i] instanceof Array) && (array[i] instanceof Array)) {
          console.log("数组中检测到数组", this[i], array[i])
          // recurse into the nested arrays
          if (!this[i].equals(array[i]))
            return false;
        } else if ((this[i] instanceof Object && array[i] instanceof Object)) {
          console.log("数组中检测到对象")
          if (!this[i].equals(array[i]))
            return false;
        } else if (this[i] != array[i]){
          // Warning - two different object instances will never be equal: {x:20} != {x:20}
          return false;
        }
      }
      return true;
    }
    Object.prototype.equals = function (object2) {
      // console.log(object2)
      for (var propName in this) {
        // console.log("对象值不一样")
        if (this.hasOwnProperty(propName) != object2.hasOwnProperty(propName)) {
          return false;
        }
        //Check instance type
        else if (typeof this[propName] != typeof object2[propName]) {
          return false;
        }
      }
      //Now a deeper check using other objects property names
      for (propName in object2) {
        if (this.hasOwnProperty(propName) != object2.hasOwnProperty(propName)) {
          return false;
        }
        else if (typeof this[propName] != typeof object2[propName]) {
          return false;
        }
        //If the property is inherited, do not check any more (it must be equa if both objects inherit it)
        if (!this.hasOwnProperty(propName))
          continue;
        if (this[propName] instanceof Array && object2[propName] instanceof Array) {
          // recurse into the nested arrays
          if (!this[propName].equals(object2[propName]))
            return false;
        }
        else if (this[propName] instanceof Object && object2[propName] instanceof Object) {
          //console.log("Recursing to compare ", this[propName],"with",object2[propName], " both named \""+propName+"\"");
          if (!this[propName].equals(object2[propName]))
            return false;
        }
        //Normal value comparison for strings and numbers
        else if (this[propName] !== object2[propName]) {
          console.log("对象值不一样", this[propName], object2[propName])
          return false;
        }
      }
      //If everything passed, let's say YES
      return true;
    }
    console.log(arr.equals(arr2))

注意：数组的比较注意下标 如果位置不一样值一样 仍return false