257. Binary Tree Paths 二叉树路径

Given a binary tree, return all root-to-leaf paths.

For example, given the following binary tree:

   1
 /   \
2     3
 \
  5

All root-to-leaf paths are:

["1->2->5", "1->3"]

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None
class Solution(object):
    def binaryTreePaths(self, root):
        if not root:
            return []
        result = []
        self.dfs(root, result, "")
        return result
    def dfs(self, node, result, string):
        if not node.left and not node.right:
            result.append(string + str(node.val))
        if node.left:
            self.dfs(node.left, result, string + str(node.val) + "->")
        if node.right:
            self.dfs(node.right, result, string + str(node.val) + "->")
        

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