[Project Euler] Problem 25
The Fibonacci sequence is defined by the recurrence relation:
Fn = Fn1 + Fn2, where F1 = 1 and F2 = 1.
Hence the first 12 terms will be:
F1 = 1
F2 = 1
F3 = 2
F4 = 3
F5 = 5
F6 = 8
F7 = 13
F8 = 21
F9 = 34
F10 = 55
F11 = 89
F12 = 144
The 12th term, F12, is the first term to contain three digits.
What is the first term in the Fibonacci sequence to contain 1000 digits?
这道题的思路很简单
我们编写一个“大数类”
重载加法运算符,编写方法判断最高位是否大于0
代码如下:
#include <iostream>
usingnamespace std;
class BigNumber
{
private:
int num[1000];
public:
BigNumber(int tmp)
{
for(int i=999; i>=0; i--)
{
num[i] = tmp%10;
tmp /=10;
}
}
public:
bool isThousand()
{
return num[0]>0;
}
BigNumber operator+(const BigNumber& bigNumber)
{
BigNumber sum(0);
int tmp;
int over =0;
for(int i=999; i>=0; i--)
{
tmp = num[i]+bigNumber.num[i]+over;
sum.num[i] = tmp%10;
over = tmp/10;
}
return sum;
}
void print()
{
for(int i=0; i<1000; i++)
{
cout << num[i];
}
cout << endl;
}
};
int main()
{
BigNumber A1(1);
BigNumber A2(1);
int i =2;
while(1)
{
i++;
A1 = A1+A2;
if(A1.isThousand())
{
break;
}
i++;
A2 = A1+A2;
if(A2.isThousand())
{
break;
}
}
cout << i << endl;
return0;
}
usingnamespace std;
class BigNumber
{
private:
int num[1000];
public:
BigNumber(int tmp)
{
for(int i=999; i>=0; i--)
{
num[i] = tmp%10;
tmp /=10;
}
}
public:
bool isThousand()
{
return num[0]>0;
}
BigNumber operator+(const BigNumber& bigNumber)
{
BigNumber sum(0);
int tmp;
int over =0;
for(int i=999; i>=0; i--)
{
tmp = num[i]+bigNumber.num[i]+over;
sum.num[i] = tmp%10;
over = tmp/10;
}
return sum;
}
void print()
{
for(int i=0; i<1000; i++)
{
cout << num[i];
}
cout << endl;
}
};
int main()
{
BigNumber A1(1);
BigNumber A2(1);
int i =2;
while(1)
{
i++;
A1 = A1+A2;
if(A1.isThousand())
{
break;
}
i++;
A2 = A1+A2;
if(A2.isThousand())
{
break;
}
}
cout << i << endl;
return0;
}
我们看到第4782个数有1000位
恭喜成功晋级到Level 1 了。