mysql where in 字符串分割无法查询数据换种思路FIND_IN_SET

select barType from bar_info where orderId='H5201702154317';

用字典表联查后使用group_concat将分组结果连接，得到期望结果：

select group_concat(dtValue) from dictionary where dtType='bar_type' and dtKey in (1,2,3,4,5,6);

但是，当代入子查询时，结果是NULL，无法得到预期结果：

select group_concat(dtValue) from dictionary where dtType='bar_type' and dtKey in (select barType from bar_info where orderId='H5201702154317') ;

这是因为 where in + 字符串，代入的是'1,2,3,4,5,6'，并不是 '1','2','3','4','5','6'，再尝试按拼接参数格式的思路去走：

使用concat(",",barType,",")，再replace(),像这样：concat(",",barType,",")：

select replace(concat("'",barType,"'"),",","','") from bar_info where orderId='H5201702154317';

联合字典表查询：

select group_concat(dtValue) ,barType from dictionary ,bar_info where dtType='bar_type' and dtKey in (replace(concat("'",barType,","),",","','")) and orderId='H5201702154317';

说明按拼接参数格式的思路也行不通。

这个时候FIND_IN_SET(str,strlist)函数可以出场了。

参数str 要查询的字符串

参数strlist 字段名 参数以”,”分隔 如 (1,2,6,8)

查询字段(strlist)中包含(str)的结果，返回结果记录就是预期。

select group_concat(dtValue) ,barType from dictionary , bar_info  where dtType='bar_type' and FIND_IN_SET(dtKey,barType) and orderId='H5201702154317';