java算法:基于应用ADT例子
java算法:基于应用ADT例子
例1:多项式ADT接口
- class Poly{
- Poly(int,int)
- double eval(double)
- void add(Poly)
- void mult(Poly)
- public String toString()
- }
例2:多项式客户程序
- public class Binomial{
- public static void main(String args[]){
- int N = 100;
- double p = 1.1;
- Poly y = new Poly(1,0);
- Poly t = new Poly(1,0);
- t.add(new Poly(1,1));
- for(int i = 0; i < N; i++){
- y.mult(t);
- System.out.println(y + " ");
- }
- System.out.println("value: " + y.eval(p));
- }
- }
例3:多项式ADT的数组实现
- class Poly{
- private int n;
- private int[] a;
- Poly(int c,int N){
- a = new int[N+1];
- n = N + 1;
- a[N] = c;
- for(int i = 0; i < N; i++){
- a[i] = 0;
- }
- }
- double eval(double d){
- double t = 0.0;
- for(int i = n - 1; i >= 0; i--){
- t = t * d + (double)a[i];
- }
- return t;
- }
- void add(Poly p){
- int[] t = new int[(p.n > n) ? p.n : n];
- for(int i = 0; i < p.n; i++){
- t[i] = p.a[i];
- }
- for(int j = 0; j < n; j++){
- t[j] += a[j];
- }
- a = t;
- n = t.length;
- }
- void mult(Poly p){
- int[] t = new int[p.n + n -1];
- for(int i = 0; i < p.n; i++){
- for(inti j = 0; j < n; j++){
- t[i+j] += p.a[i] * a[j];
- }
- }
- a = t;
- n = t.length;
- }
- public String toString(){
- String s = "";
- for(int i = 0; i < n; i++){
- s += a[i] + " ";
- }
- return s;
- }
- }
注意:Horner算法:a4x4 + a3x3 + a2x2 + a1x + a0 = (((a4x + a3)x + a2)x + a1)x + a0