HDU 2191

思路：简单动态规划，多重背包转化成0 1背包问题

#include<stdio.h>
#include<string.h>
int a[101][2001],rcw[2001],rcp[2001];
int max(int x,int y)
{
    return x>y?x:y;
}

int main()
{
    int C,i,j,k,pg,n,m,pr,w;
    scanf("%d",&C);
    while(C--)
    {
        memset(a,0,sizeof(a));
        k = 0;
        scanf("%d%d",&n,&m);
        for(i = 0;i < m;i ++)
        {
            scanf("%d%d%d",&pr,&w,&pg);
            for(j = k;j < k+pg;j ++)
            {
                rcw[j] = w;
                rcp[j] = pr;
            }
            k = j;
        }
        for(i = 1;i <= n;i ++)
        {
            for(j = 0;j < k;j ++)
            {
                if(i>=rcp[j])
                    a[i][j] = max(a[i][j-1],a[i-rcp[j]][j-1]+rcw[j]);
                else
                    a[i][j] = a[i][j-1];
            }
        }
        printf("%d\n",a[n][k-1]);
    }
    return 0;
}