hdoj 1025 Constructing Roads In JGShining's Kingdom(最长上升子序列+二分)

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1025

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 1 #include <iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 #define maxn 500010
 5 using namespace std;
 6 int a[maxn];
 7 int b[maxn];//存储序列长度为len的第i小的数中最小的数
 8 int dp[maxn];
 9 int chazhao(int x,int l,int r)//查找第i-1的长度序列中,结尾比a[i]小的最大长度
10 {
11     int mid;
12     while(l<=r)
13     {
14         mid=(l+r)/2;
15         if(b[mid]<=x)
16         l=mid+1;
17         else
18         r=mid-1;
19     }
20     return r;
21 }
22 int main()
23 {
24     int x,y,i,n,k=0,len;
25     while(scanf("%d",&n)!=EOF)
26     {
27         k++;
28         for(i=0;i<n;i++)
29         {
30             scanf("%d%d",&x,&y);
31             a[x]=y;
32         }
33         memset(b,-1,sizeof(b));
34         dp[1]=1;
35         b[1]=a[1];
36         len=1;
37         for(i=2;i<=n;i++)
38         {
39             int max=chazhao(a[i],1,len);
40             dp[i]=max+1;
41             if(b[i]==-1||b[dp[i]]>a[i])//更新b
42             b[dp[i]]=a[i];
43             if(len<dp[i])
44             len=dp[i];
45         }
46         if(len==1)
47         {
48             printf("Case %d:\n",k);
49         printf("My king, at most %d road can be built.\n\n",len);
50         }
51         else
52         {
53               printf("Case %d:\n",k);
54         printf("My king, at most %d roads can be built.\n\n",len);
55         }
56 
57     }
58     return 0;
59 }
posted @ 2012-10-19 21:13  琳&leen  阅读(119)  评论(0编辑  收藏  举报