MySQL 根据当前日期,查询24个小时每小时的数量,为null填充0

1、时间字段是datetime类型

2、需要用到中间表,表结构和数据链接下载

链接:https://pan.baidu.com/s/1tAFU4nm1p4CkSneXwceA_A 
提取码:b3xi 

3、sql

select
    CREATEDATE as YYmmdd,
    CONCAT(CREATEDATE,' ',d.i) YYmmddHH,
    d.i as HH,
    case when zscum is null then 0 else zscum end as zscum
from
    ( 
    select
    DATE_FORMAT(CREATEDATE,'%Y-%m-%d') as CREATEDATE,
    SUM(CASE WHEN e.status = '1' THEN 1 ELSE 0 END ) AS zscum,
    HOUR ( CREATEDATE ) as hour
    from event_base_info e
    -- 自己的条件
    where e.status='1' and  e.STATE not in('3702820001') 
    -- 时间
    and DATE_FORMAT( CREATEDATE, '%Y-%m-%d' ) like '2019-06-04%' 
    GROUP BY HOUR ( CREATEDATE ) 
    ) o
    -- 中间表
    RIGHT JOIN ( select i from num where i between '0' and '24' ) d on o.hour = d.i 
GROUP BY d.i

5、效果 (HH是小时,用了中间表)

 

如有疏漏,请指正!谢谢

 

posted @ 2019-06-04 22:53  雁书几封  阅读(1450)  评论(0编辑  收藏  举报