[LeetCode] Binary Tree Preorder Traversal

Given a binary tree, return the preorder traversal of its nodes' values.

For example:
Given binary tree {1,#,2,3},

   1
    \
     2
    /
   3

 

return [1,2,3].

Note: Recursive solution is trivial, could you do it iteratively?

 

思路：用栈。之间复杂度O(n),空间复杂度O(n)

　　

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    vector<int> preorderTraversal(TreeNode *root) {
        vector<int> result;
        stack<TreeNode*> s;
        TreeNode *p = root;
        
        while (p != NULL || !s.empty()) {
            if (p != NULL) {
                result.push_back(p->val);
                s.push(p);
                p = p->left;
            } else {
                p = s.top();
                s.pop();
                p = p->right;
            }
        }
         return result;
    }
};