hdu 3061 Battle 最大权闭合图
#include <cstdio> #include <cstring> #include <vector> #include <queue> using namespace std; #define maxn 1000 #define INF 100000 struct Edge { int from, to, cap, flow; }; int n, m, s, t; vector<Edge> edges; // 边数的两倍 vector<int> G[maxn]; // 邻接表,G[i][j]表示结点i的第j条边在e数组中的序号 bool vis[maxn]; // BFS使用 int d[maxn]; // 从起点到i的距离 int cur[maxn]; // 当前弧指针 int min(int a,int b) { if(a<b) return a; else return b; } void AddEdge(int from, int to, int cap) { int len; Edge temp; temp.from=from;temp.to=to;temp.cap=cap;temp.flow=0; edges.push_back(temp); temp.from=to;temp.to=from;temp.cap=0;temp.flow=0; edges.push_back(temp); len = edges.size(); G[from].push_back(len-2); G[to].push_back(len-1); } bool BFS() { memset(vis, 0, sizeof(vis)); queue<int> Q; Q.push(s); vis[s] = 1; d[s] = 0; while(!Q.empty()) { int x = Q.front(); Q.pop(); for(int i = 0; i < G[x].size(); i++) { Edge& e = edges[G[x][i]]; if(!vis[e.to] && e.cap > e.flow) { vis[e.to] = 1; d[e.to] = d[x] + 1; Q.push(e.to); } } } return vis[t]; } int DFS(int x, int a) { if(x == t || a == 0) return a; int flow = 0, f; for(int& i = cur[x]; i < G[x].size(); i++) { Edge& e = edges[G[x][i]]; if(d[x] + 1 == d[e.to] && (f = DFS(e.to, min(a, e.cap-e.flow))) > 0) { e.flow += f; edges[G[x][i]^1].flow -= f; flow += f; a -= f; if(a == 0) break; } } return flow; } int Maxflow() { int flow = 0; while(BFS()) { memset(cur, 0, sizeof(cur)); flow += DFS(s, INF); } return flow; } int main() { int i,x,y; while(scanf("%d%d",&n,&m)!=EOF) { int sum=0; for(i=0;i<=n+10;i++) G[i].clear(); s=0;t=n+1; for(i=1;i<=n;i++) { scanf("%d",&x); if(x>0) { AddEdge(s,i,x); sum+=x; } else if(x<0) AddEdge(i,t,-x); } for(i=1;i<=m;i++) { scanf("%d%d",&x,&y); AddEdge(x,y,INF); } printf("%d\n",sum-Maxflow()); } return 0; }