Release+非MFC不能使用VERIFY如何产生中断

网上看到有些人是自己封装了一些中断函数,比如调用__asm{INT 21H};等。
突然想到,可以直接用C++语言本身提供的try..catch语句啊。FOOL -.-

写了一个测试类:

#pragma once

#include <windows.h>
#include <iostream>
using namespace std;

class CTestClass
{
public:
    CTestClass(UINT64 qwPosBegin, UINT64 qwPosEnd)
    {
        try
        {
            INT64 qwSize = (INT64)(qwPosEnd - qwPosBegin);
            if(qwSize < 0)
                throw qwSize;

            m_qwPosBegin = qwPosBegin;
            m_qwPosEnd = qwPosEnd;
            m_qwSize = m_qwPosEnd - m_qwPosBegin;
        }
        catch(INT64 &qwSize)
        {
            const int BUF_LEN = 100;
            WCHAR szBuff[BUF_LEN] = {0};
            swprintf(szBuff, BUF_LEN, L"Segment length is negative! Value: %I64d", qwSize);
            ::MessageBoxW(NULL, szBuff, L"Error", MB_OK|MB_ICONERROR);
//delete this; } }
~CTestClass() { cout<<"This is Destruct Method"<<endl; m_qwPosBegin = 0; m_qwPosEnd = 0; m_qwSize = 0; OutputInfo(); } void OutputInfo() { cout<<"Pos Begin:\t"<<m_qwPosBegin<<endl; cout<<"Pos End:\t"<<m_qwPosEnd<<endl; cout<<"Segment Len:\t"<<m_qwSize<<"\n"<<endl; } private: UINT64 m_qwPosBegin;//using UING64 instead of INT64 to contain as more data as possible UINT64 m_qwPosEnd; UINT64 m_qwSize; };

调用代码:

void main()
{
#define SAFE_DELETE_OBJECT(obj) if(obj) { delete obj; obj = NULL;}

    CTestClass* obj1 = new CTestClass(10, 100);
    if(obj1)
        obj1->OutputInfo();

    
    CTestClass* obj2 = new CTestClass(100, 10);
    if(obj2)
        obj2->OutputInfo();

    SAFE_DELETE_OBJECT(obj1);
    SAFE_DELETE_OBJECT(obj2);

    system("pause");
}

测试输出结果:

Pos Begin:      10
Pos End:        100
Segment Len:    90

Pos Begin:      13451671603782742029
Pos End:        13451671603782742029
Segment Len:    13451671603782742029

This is Destruct Method
Pos Begin:      0
Pos End:        0
Segment Len:    0

This is Destruct Method
Pos Begin:      0
Pos End:        0
Segment Len:    0

请按任意键继续. . .

一点解释:throw之后就会跳出整个try块,因此可能出问题的代码要写在最前面--所谓“要写异常安全的函数”  呵呵 有歧义 这里的"异常"是“Exception” n. ,而非“Extraordinary” adj. 的意思 -.-

posted @ 2013-12-21 17:23  Tup  阅读(333)  评论(0编辑  收藏  举报