在结核菌中,以12SNP为阈值判断菌株间是否为近期传播。
利用生物信息学方法从原始测序结果得到各菌株的SNP文件,通过互相比较得到两个文件:
(1)各菌株间相互比较的情况,格式为:菌株AVS菌株B  SNP距离,总行数为n*(n-1)/2
(2)利用文件1得到近期传播的菌株列表
接下来要把这些菌株串起来,形成传播链,核心思想是:链内的任一菌株与至少1个链内其它菌株的SNP距离<=12;链内的任一菌株与链外所有菌株的距离都>12
因此,核心思想也就是“迭代”,并不断删除数据,减少计算量

import sys
import re

f1=open(sys.argv[1]).readlines() #strain distance
f2=open(sys.argv[2]).readlines() #distance <= 12 strain list
f3=open("rough_transmission_chain","a")

sum_chain_list=[i.rstrip().split()[0] for i in f1 if int(i.rstrip().split()[1])<=12]

def find_transmission_strain(strain):
cycle_strain = []
match_strain = []
True_strain = [i for i in sum_chain_list if i.startswith(strain + "VS") or i.endswith("VS" + strain)]
for item in True_strain:
temp = re.sub("VS", "", item)
sum_chain_list.remove(item)
if temp[:len(strain)] == strain:
match_strain.append(temp[len(strain):])
cycle_strain.append(temp[len(strain):])
else:
match_strain.append(temp[0:len(temp) - len(strain)])
cycle_strain.append(temp[0:len(temp) - len(strain)])
if len(cycle_strain) > 0:
for a in range(len(cycle_strain)):
for b in range(len(cycle_strain)):
try:
sum_chain_list.remove(cycle_strain[a] + "VS" + cycle_strain[b])
except ValueError as e:
pass
for i in cycle_strain:
match_strain.extend(find_transmission_strain(i))
return set(match_strain)

temp = []

for i in f2:
i = i.rstrip()
if i not in temp:
a = list(find_transmission_strain(i))
a.append(i)
temp.extend(a)
for strain in a:
f3.write(strain + "\t")
f3.write("\n")

else:
pass