MongoTemplate distinct

Query query = new Query(Criteria.where("mId").is(mId).and("dr").is(0));
List result = mongoTemplate.getCollection("user").distinct("tableNo",query.getQueryObject());

posted @ 2016-12-28 10:52  天天爱开心  阅读(2174)  评论(0编辑  收藏  举报