线段树区间增加/赋值 求区间和最大值最小值

 1 /*
 2 maxnode为区间长度的三倍
 3 调用:
 4 tree.update(1, 1, n);
 5 tree.query(1, 1, n, 0);
 6 n为区间长度,[y11, y22]为维护或查询区间,v为增加值或修改值
 7 op == 1时区间加上v,op == 2时区间修改为v
 8 */
 9 const int maxnode = 100000 * 3;
10 int _sum, _min, _max, op, y11, y22, v;
11 struct IntervalTree {
12   int sumv[maxnode], minv[maxnode], maxv[maxnode], setv[maxnode], addv[maxnode];
13 
14   // 维护信息
15   void maintain(int o, int L, int R) {
16     int lc = o*2, rc = o*2+1;
17     if(R > L) {
18       sumv[o] = sumv[lc] + sumv[rc];
19       minv[o] = min(minv[lc], minv[rc]);
20       maxv[o] = max(maxv[lc], maxv[rc]);
21     }
22     if(setv[o] >= 0) { minv[o] = maxv[o] = setv[o]; sumv[o] = setv[o] * (R-L+1); }
23     if(addv[o]) { minv[o] += addv[o]; maxv[o] += addv[o]; sumv[o] += addv[o] * (R-L+1); }
24   }
25 
26   // 标记传递
27   void unmark(int o) {
28     int lc = o*2, rc = o*2+1;
29     if(setv[o] >= 0) {
30       setv[lc] = setv[rc] = setv[o];
31       addv[lc] = addv[rc] = 0;
32       setv[o] = -1; // 清除本结点标记
33     }
34     if(addv[o]) {
35       addv[lc] += addv[o];
36       addv[rc] += addv[o];
37       addv[o] = 0; // 清除本结点标记
38     }
39   }
40 
41   void update(int o, int L, int R) {
42     int lc = o*2, rc = o*2+1;
43     if(y11 <= L && y22 >= R) { // 标记修改
44       if(op == 1) addv[o] += v;
45       else { setv[o] = v; addv[o] = 0; }
46     } else {
47       unmark(o);
48       int M = L + (R-L)/2;
49       if(y11 <= M) update(lc, L, M); else maintain(lc, L, M);
50       if(y22 > M) update(rc, M+1, R); else maintain(rc, M+1, R);
51     }
52     maintain(o, L, R);
53   }
54 
55   void query(int o, int L, int R, int add) {
56     if(setv[o] >= 0) {
57       int v = setv[o] + add + addv[o];
58       _sum += v * (min(R,y22)-max(L,y11)+1);
59       _min = min(_min, v);
60       _max = max(_max, v);
61     } else if(y11 <= L && y22 >= R) {
62       _sum += sumv[o] + add * (R-L+1);
63       _min = min(_min, minv[o] + add);
64       _max = max(_max, maxv[o] + add);
65     } else {
66       int M = L + (R-L)/2;
67       if(y11 <= M) query(o*2, L, M, add + addv[o]);
68       if(y22 > M) query(o*2+1, M+1, R, add + addv[o]);
69     }
70   }
71 } tree;

 

posted @ 2015-08-24 23:30  不会起昵称  阅读(997)  评论(0编辑  收藏  举报